By Andreas Kriegl

This ebook lays the rules of differential calculus in endless dimensions and discusses these purposes in countless dimensional differential geometry and international research no longer concerning Sobolev completions and glued aspect idea. The strategy is easy: a mapping is named delicate if it maps tender curves to tender curves. as much as Fréchet areas, this concept of smoothness coincides with all identified average thoughts. within the similar spirit, calculus of holomorphic mappings (including Hartogs' theorem and holomorphic uniform boundedness theorems) and calculus of genuine analytic mappings are constructed. lifestyles of soft walls of solidarity, the rules of manifold thought in countless dimensions, the relation among tangent vectors and derivations, and differential kinds are mentioned completely. distinctive emphasis is given to the inspiration of normal endless dimensional Lie teams. Many functions of this conception are integrated: manifolds of delicate mappings, teams of diffeomorphisms, geodesics on areas of Riemannian metrics, direct restrict manifolds, perturbation concept of operators, and differentiability questions of endless dimensional representations.

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**Example text**

Obviously, any composition of smooth mappings is also smooth. Lemma. The space C ∞ (U, F ) is the (inverse) limit of spaces C ∞ (R, F ), one for each c ∈ C ∞ (R, U ), where the connecting mappings are pull backs g ∗ along reparameterizations g ∈ C ∞ (R, R). Note that this limit is the closed linear subspace in the product C ∞ (R, F ) c∈C ∞ (R,U ) consisting of all (fc ) with fc◦g = fc ◦ g for all c and all g ∈ C ∞ (R, R). Proof. The mappings c∗ : C ∞ (U, F ) → C ∞ (R, F ) define a continuous linear emg∗ bedding C ∞ (U, F ) → limc {C ∞ (R, F ) −→ C ∞ (R, F )}, since c∗ (f ) ◦ g = f ◦ c ◦ g = (c ◦ g)∗ (f ).

Indeed for c(t) = 0 this is clear and for c(t) = 0 it follows from f (0)(v) = f (v). The directional derivative of the 1-homogeneous mapping f is 0-homogeneous: In fact, for s = 0 we have f (sx)(v) = ∂ ∂t f (s x + tv) = s t=0 For any s ∈ R we have f (s v)(v) = ∂ ∂t t 1 f (x + v) = s f (x)( v) = f (x)(v). s s t=0 ∂ ∂t |t=0 f (s v + tv) = ∂ ∂t |t=s t f (v) = f (v). Using this homogeneity we show next, that it is also continuously differentiable along continuously differentiable curves. So we have to show that (f ◦ c) (t) → (f ◦ c) (0) for t → 0.

F ◦ c) (0) exists, provided c (0) exists. Only the case c(0) = 0 is not trivial. Since c is differentiable at 0 the curve c1 defined by c1 (t) := c(t) t for t = 0 and c (0) for t = 0 is continuous at 0. Hence f (c(t))−f (c(0)) f (t c1 (t))−0 = = f (c1 (t)). This converges to f (c1 (0)), since f is cont t tinuous. 3 3. Smooth mappings and the exponential law 25 Furthermore, if f (x)(v) denotes the directional derivative, which exists everywhere, then (f ◦ c) (t) = f (c(t))(c (t)). Indeed for c(t) = 0 this is clear and for c(t) = 0 it follows from f (0)(v) = f (v).